(2x+7)(5x^2-12x+4)=0

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Solution for (2x+7)(5x^2-12x+4)=0 equation: 


Simplifying
(2x + 7)(5x2 + -12x + 4) = 0

Reorder the terms:
(7 + 2x)(5x2 + -12x + 4) = 0

Reorder the terms:
(7 + 2x)(4 + -12x + 5x2) = 0

Multiply (7 + 2x) * (4 + -12x + 5x2)
(7(4 + -12x + 5x2) + 2x * (4 + -12x + 5x2)) = 0
((4 * 7 + -12x * 7 + 5x2 * 7) + 2x * (4 + -12x + 5x2)) = 0
((28 + -84x + 35x2) + 2x * (4 + -12x + 5x2)) = 0
(28 + -84x + 35x2 + (4 * 2x + -12x * 2x + 5x2 * 2x)) = 0
(28 + -84x + 35x2 + (8x + -24x2 + 10x3)) = 0

Reorder the terms:
(28 + -84x + 8x + 35x2 + -24x2 + 10x3) = 0

Combine like terms: -84x + 8x = -76x
(28 + -76x + 35x2 + -24x2 + 10x3) = 0

Combine like terms: 35x2 + -24x2 = 11x2
(28 + -76x + 11x2 + 10x3) = 0

Solving
28 + -76x + 11x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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